Going home
A chauffeur always arrives at the train station at exactly five o'clock to pick up his boss and drive her home. One day his boss arrives an hour early, starts walking home, and is picked up by the chauffeur on the way out to the train station. They arrive at home twenty minutes earlier than usual. How long did she walk before she met her chauffeur?
Labels: mathschallenge
posted by Chris at
7:51 AM
7 Comments:
I guess that she walked for 50 mins.
The chauffeur would have then met her at 4:50 and as a result he would have saved 10 mins of his outward journey, and 10 mins of his homebound journey, thus getting him (and his boss) back home 20 mins earlier than normal.
Depends how long they stopped along the way for a bit of . . . er . . . recreational activity.
(This post has been removed by the ToM censor).
Building on Dual's idea ... wouldn't she have walked for 70 minutes. She starts at 4PM ... at 5:10PM, the chauffeur picks her up saving 10 minutes of his normal drive to the statopn ... which would save another 10 on the trip home ... thus a 20 minute savings and 20 minute early arrival time.
DualAspect, you got it. Well done.
Disregard earlier post .. I see the error of ways
Good thinking, DA. I must admit that I couldn't see how to crack this, then got distracted by other thoughts.
I thought that one was going to last a bit longer.
Post a Comment
Links to this post:
Create a Link
<< Home