Ball on an Inclined Plane
Place a ball at the top of an inclined plane (a wedge). Release the ball and allow it to travel for one second, stop it. Mark the distance it traveled on the plane. Measure the distance traveled and divide the remainder of the plane surface into segments equal to the distance the ball traveled in one second.
Perform the same experiment 4 more times, how many segments will it travel in:
2 seconds -> ?
3 seconds -> ?
4 seconds -> ?
5 seconds -> ?
Perform the same experiment 4 more times, how many segments will it travel in:
2 seconds -> ?
3 seconds -> ?
4 seconds -> ?
5 seconds -> ?
posted by Zaux at
9:46 PM
5 Comments:
Ball on inclined plane
Uniformly accelerated body
d=0.5*a*t^2+vo*t
vo=0
d=0.5*a*t^2
d(1)=0.5*a*1^2=0.5*a
d(2)=0.5*a*2^2=2*a=4*d(1)
d(3)=0.5*a*3^2=4.5*a=9*d(1)
d(4)=0.5*a*4^2=8*a=16*d(1)
d(5)=0.5*a*5^2=12.5*a=25*d(1)
Answer:
2s-4 segments
3s-9 segments
4s-16 segments
5s-25 segments
Cam
Works even if the inclined plane is not a wedge, but a straight plank raised at one end by a brick. :-)
Hi Cam ... you don't need my verification, but that is correct
I agree with Cam. However, at what point will it stop accelerating and reach a uniform speed? Let's see it in graph form to make it easy...
Karl, you cannot be serious. Have you tried including a graph in a comment post?
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