The Rope Problem
Assume, we lay a rope tightly around the Planet and then elongate this rope by just 1 meter and then evenly distribute this additional length around the whole equator.
What is the extra length of the Rope required ?
What is the extra length of the Rope required ?
Labels: logic, mathemagic
posted by Rajesh Lal at
7:32 AM
13 Comments:
1 meter of rope was added, so thats all thats required to be evenly distributed.. 1 meter
The question hasn't been written correctly.
If it meant elongate the rope by 1 metre, then it can hover! 2π meters above the ground.
If it meant it is hovering 1 metre above the ground, then it needs to be elongated by 1/(2π) metres.
I suspected the post wasn't correct, but it could be a trick
The answer was obviously 1 meter.
Chris,
You can edit your post. When I make a post, I usely read it after posting, and often go back and edit it. Sometimes I may add additional info. I suppose you could wait a day two and change it so that all the comments look wrong. But that wouldn't be nice, would it.
This post has been removed by the author.
Maybe not. since the change is 1 unit, maybe 1/(2pi) was correct.
I got the increase in the circumference would be 2*pi or the inverse of your answer, Chris.
oic
I finally re-read you comment where you explained the post.
Hi Ragknot. I do edit my own posted problems. I've updated the "What a shot!" problem.
... but I make it clear when I've edited.
I submitted a comment for What a shot.
Chris has got it the wrong way round. If you add 1m to the rope, it could equally hover ~16cm (1/2π m)over ground, to make it hover 1m you would have to lenthen it by ~6.28m (2π m).
This post has been removed by the author.
mo, well spotted. I goofed when editing. Too busy playing with π rather than pi. I realise that Ragknot was warning me that I goofed as well.
Post a Comment
Links to this post:
Create a Link
<< Home