A widely debated topic... My view is that fluid mechanics isn't needed for this problem. Pressure answers all of my questions. Think of it like this....
Once the tube is filled (through suction, initial condition, whatever the case may be), the low end or discharge side is at atmospheric pressure, right (assuming the container to be filled is empty)? The suction side is at atmospheric pressure pressure PLUS the level of liquid in the container being drained. A simple delta P drives the transfer.
OK.. yes, there is a higher energy state that must be overcome in between if you think about it on a microscopic level. The fluid must overcome gravity to get past the high point, right? Well, not as I think of it. You see, once the tube is filled, gravity acts on both sides of the high point of the hose equally. Since both sides cannot be drained to the lower energy state (because a vacuum would be pulled), it must be that they cancel each other out in a way. And, back to my original point, macroscopically, you have atmospheric pressure on one end and on the other you have atm PLUS the level of liquid.
A siphon is a consequence of pressure, which is a consequence of gravity. That's my two cents.
i believe it's more of a weight issue than a pressure issue. The highest point is the divider. If the fluid will travel from the side with the lesser fluid to the side with the greater fluid. That's because the fluid weighs more on that side, so it drains off. but as long as no air can come into the tube, then it draws fluid from the lighter side (suction), which draw more fluid from the source containter into the tube. If air can come into the tube freely, then the siphon will stop working.
An interesting way of looking at it, but no. It is pressure driven. Think about it. At the apex of the siphon tube, gravity "pulls" the water down on both sides. Using your methodology the siphon tube would not work, a full siphon tube would be drained in both directions from the apex.
how so jessy? there would b no air to let the water move from the middle out, like when u have a staw and u put it in a soda, the straw fills up to the level of the soda, if u put ur finger over the top of the staw the water stays, no air to go in, it holds the water there (sucktion) to make a siphon work u have to force water to move past the apex of your siphon, once the water goes over the suction of the water on the discharge side pulls the water form then entrance side up and over, thus continuing untill air gets in and breaks the vaccum
I agree with you. My point was that the only coherent way to explain a siphon is with pressure. There are other accepted explanations... but pressure is the only one that makes sense to me.
But let me propose a question (I hope someone posts this as an actual trick of mind question):
Would a siphon work if: the elevation of the apex of the siphon tube minus the elevation of the suction point is greater than the elevation of the suction point minus the elevation of the discharge point?
Using symbols, If (Eapex - Esuction) > (Esuction - Edischarge), would a siphon work?
Why?
*Assume there is 1 foot of water above the suction and discharge of the siphon tube.
12 Comments:
homework question, Rag, dont answer it
presure
Air pressure, water level, blah blah. I wan't a harder question.
>:(
one word for dummies.
Sucks
This post has been removed by the author.
This post has been removed by the author.
A widely debated topic... My view is that fluid mechanics isn't needed for this problem. Pressure answers all of my questions. Think of it like this....
Once the tube is filled (through suction, initial condition, whatever the case may be), the low end or discharge side is at atmospheric pressure, right (assuming the container to be filled is empty)? The suction side is at atmospheric pressure pressure PLUS the level of liquid in the container being drained. A simple delta P drives the transfer.
OK.. yes, there is a higher energy state that must be overcome in between if you think about it on a microscopic level. The fluid must overcome gravity to get past the high point, right? Well, not as I think of it. You see, once the tube is filled, gravity acts on both sides of the high point of the hose equally. Since both sides cannot be drained to the lower energy state (because a vacuum would be pulled), it must be that they cancel each other out in a way. And, back to my original point, macroscopically, you have atmospheric pressure on one end and on the other you have atm PLUS the level of liquid.
A siphon is a consequence of pressure, which is a consequence of gravity. That's my two cents.
Jesse
i believe it's more of a weight issue than a pressure issue. The highest point is the divider. If the fluid will travel from the side with the lesser fluid to the side with the greater fluid. That's because the fluid weighs more on that side, so it drains off. but as long as no air can come into the tube, then it draws fluid from the lighter side (suction), which draw more fluid from the source containter into the tube. If air can come into the tube freely, then the siphon will stop working.
An interesting way of looking at it, but no. It is pressure driven. Think about it. At the apex of the siphon tube, gravity "pulls" the water down on both sides. Using your methodology the siphon tube would not work, a full siphon tube would be drained in both directions from the apex.
Jesse
how so jessy? there would b no air to let the water move from the middle out, like when u have a staw and u put it in a soda, the straw fills up to the level of the soda, if u put ur finger over the top of the staw the water stays, no air to go in, it holds the water there (sucktion) to make a siphon work u have to force water to move past the apex of your siphon, once the water goes over the suction of the water on the discharge side pulls the water form then entrance side up and over, thus continuing untill air gets in and breaks the vaccum
I agree with you. My point was that the only coherent way to explain a siphon is with pressure. There are other accepted explanations... but pressure is the only one that makes sense to me.
But let me propose a question (I hope someone posts this as an actual trick of mind question):
Would a siphon work if: the elevation of the apex of the siphon tube minus the elevation of the suction point is greater than the elevation of the suction point minus the elevation of the discharge point?
Using symbols, If (Eapex - Esuction) > (Esuction - Edischarge), would a siphon work?
Why?
*Assume there is 1 foot of water above the suction and discharge of the siphon tube.
Jesse
suck it and see!
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