It is a very good probability that 2 people will have the exact same numbers of hair on their heads. One of the most common styles for men is being bald. Bald = 0 hairs.
However if you meant hairs on the entire body, then that probability would be very different
Consider the N numbers b1 = (a1) mod(N), b2 =(a1 + a2) mod(N), b3 = (a1+a2+a3) mod(N), ..., bN = (a1 + ... + aN) mod(N). If one of these numbers is zero, then we are done. Otherwise, only the N-1 numbers 1, 2, ..., N-1 are represented in this list, and so two of them must be the same, bi = bj (say i < j). This would then imply that (ai+1 + ... + aj) mod(N) = 0
The number of hairs on either your head or your body is not a static number. It's a dynamic number. We shed and regrow hair constantly throughout the day. By the time you counted the hairs on a persons hiar, the number would already be inaccurate.
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It is a very good probability that 2 people will have the exact same numbers of hair on their heads. One of the most common styles for men is being bald. Bald = 0 hairs.
However if you meant hairs on the entire body, then that probability would be very different
It's a certainty due to the pigeon hole principal.
100%
there are at least 6billion people in the world, much more than the possible number of hairs on a head
100%
Some people in this world actually share a head.
Consider the N numbers b1 = (a1) mod(N), b2 =(a1 + a2) mod(N), b3 = (a1+a2+a3) mod(N), ..., bN = (a1 + ... + aN) mod(N). If one of these numbers is zero, then we are done. Otherwise, only the N-1 numbers 1, 2, ..., N-1 are represented in this list, and so two of them must be the same, bi = bj (say i < j). This would then imply that (ai+1 + ... + aj) mod(N) = 0
The number of hairs on either your head or your body is not a static number. It's a dynamic number. We shed and regrow hair constantly throughout the day. By the time you counted the hairs on a persons hiar, the number would already be inaccurate.
100%
Bald people have no hair
100%
you cant count the amount of hairs on your head... i tried...lol
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