Cattle Case
An old farmer died leaving three sons. He bequethed the first son half of his cattle, the second one third and to the third son one ninth.
He had a total of 12 cows and 5 buffalows ! Can you solve the case ?
He had a total of 12 cows and 5 buffalows ! Can you solve the case ?
Labels: mathemagic, outside-the-box, trickofmind
posted by Rajesh Lal at
9:12 AM
3 Comments:
He had a bull, for a total of 18 cattle. The first son got 9 cattle, the second 6, and the third 2, leaving 2 cattle for something else, probably to pay off debts.
He had 17 cattle total
1/2 = 8.5 round up to 9
1/3 = 5.6 round up to 6
1/9 = 1.8 round up to 2
9+6+2 = 17
Drake
haha...
lmao i read this b4
its reworded buh the answer is the same
heres the answer
a neighbour adds 1 more cattle makin it 18 in total
first son gets 1/2 aka 9
2nd son gets 1/3 aka 6
3rd son gets 1/9 aka 2
add 9 6 and 2 and you get 17
take out the remainder one and return it to the neighbour.
haha my first riddle solved b4 any1 cud solve it.
maltown
Huzzy
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