Alien Division
Alien's "calculator" scanned twenty humans in four houses, immediately six showed up in the "calculator's" display.
What will the "calculator" show if the number of humans are ten distributed in five houses?
What will the "calculator" show if the number of humans are ten distributed in five houses?
Labels: bcreative, mathemagic, outside-the-box





22 Comments:
I'll go with 3...
(houses + humans) / houses
yeah ill say 3 too...
yeah ill say 3 too...
yeah ill say 3 too...
3 :p, but aliens suck at programming!
3
20 people in four houses and the answers is 6. times 6 by 4 you get 24 which equals houses + people
10 people add 5 houses = 15 divide by 5 houses equals 3
Hey, why can't the smart people like me wait for others to try before giving away the answer?
Cannot be Three (There is no logic in the explaination given)
Why would alien add houses with humans ? They are different.
3....
1st scan is 20 humans in four houses, 20/4 or 5/1 or 6
2nd scan is 10 humans in fives hoses, or 10/5 or 2/1 or 3.
Weird logic, but that is the only pattern I can see. :)
I'm thinking outside the box and say 6 (Humans + Houses, then add the numbers in the final number together.) I guess it could be because with only 1 example it could be anything that your mind can think of
yeah, this is one of those where it works no matter which way you try it, so i could say
20 * 4 = 80 + 20 / 4 = 85 - 25 = 60 / 10 = 6
just to be random, and then try it again with the second one, so it'd be
10 * 5 = 50 + 10 / 5 = 52 - 25 = 27 / 10 = 2.7
so basically there's no right or wrong answer, therefore, i think a better question would tell you the answer from the second one, and ask you to figure out the relationship
Hmm. What would the alien want to know? How about how many people are apt to be encountered in any house. If the 20 people were divided equally you would have 5 in each of the 4 houses but that's unlikely. A 'safer' guess might be 6.
In the second case 2 in every house seems equally unlikely so I think I'd go for 3 as well.
Picking at random how many people are you going to find in a single house.
You could work out the actual (highest probability) number with standard deviation and a bell curve but that's more effort than I care to give the problem.
It makes more sense than sum of the digits (Of course 6 on an alien calculator may mean it's lunch time so the correct answer is orange)
Well, i'll give a different answer, just because I like to be different. I'll say 2.4
If the numbers are all in base 12, then 20/4 = 6 and 10/5 = 2.4
Converted to base 10 for us humans, it would be 24/4 = 6 and 12/5 = 2.4
mine is strange but i say 3 because, if distributed equal, 5 humans per house plus one in one of them for the alien to move in as after a body snatch in the first problem woulds make 6, that's the logic (i think) for the second as well
i say 3, because it's the number of letters for each number :
t w e n t y = 6
t e n = 3
20 humans in 4 houses
20/4=6
10 humans in 5 houses
10/5=2
duh
20/4=6??
nice..
Yeah, 'duh' yourself!
I am also going with the answer that you can get just about anything you want.
However, it does make sense for the answer to be three. Thinking as an earthling, that is.
to mmlauser : different anonymous :)
3 but i guess thats why they keep crashing.
ITS 2
heres why
10/5=2 because 5 goes into 10 2 times
DUH
7 or 7.5...
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